A rain gutter is to be constructed from a metal sheet of width 30 cm by bending up one-third of the sheet on each side through an angle 胃. How should 胃 be chosen so that the gutter will carry the maximum amount of water?A rain gutter is to be constructed from a metal sheet of width 30 cm by bending up one-third of the sheet on e?
It will fold like a trapezoid with bottom = 10 cm
Height = 10 sin 螛
Top of the trapezoid = 10 cos 螛 + 10 + 10 cos 螛
= 10 + 20 cos 螛
Area = (1/2)h(top + bottom)
A = (1/2)(10 sin 螛)(10 + 20 cos 螛 + 10)
A = 5 sin螛 (20 + 20 cos 螛)
A = 100 sin螛(1+cos螛)
A' = 100(cos螛)(1+cos螛) + 100(sin螛)(-sin螛)
0 = 100(cos螛+cos虏螛) - 100(sin虏螛)
100(sin虏螛) = 100(cos螛+cos虏螛)
1-cos虏螛 = cos螛+cos虏螛
0 = 2cos虏螛+cos螛-1
0 = (2cos螛 - 1)(cos螛 + 1)
cos螛 = 1/2 or -1
螛 = 蟺/3 or 蟺
The angle should be 蟺/3 because 蟺 will give zero area.
You can use second derivatives to prove 蟺/3 is the maximum point.
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