=1558.229956
=1558.23Suppose a tank is a right circular cylinder is 30ft long and has a diameter of 8ft. how many sheet of metal is
do u mean area of sheet?? then, 30*3.14*2*4+3.14*4*4
The surface of the tank contains two circular sheets to cover the upper and the lower areas of the cylinder, and the circular sheet that goes around the cylinder
The areas of the lower base and the upper cover of the tank are equal to 2* pi*r^2
The area of the circular surface that goes around the cylinder is 2pi*r*h where h is the height of the cylinder.
The total area of sheets required is:
A = 2*pi*r^2 + 2*pi*r*h. Substituting r= 4 feet and h= 30 feet:
A= 2*pi*4^2 +2*pi*4*30= 853.8 feet square
Answer is 853.8 squared feet.
im pretty sure its 1558.229956
formula = (2piR^2H) + (2piRH) = Total Area of tank
no of sheet = Total Area of tank/ Area of the sheet
sub the area of sheet
to solve the lateral area which is the body of the tank : pi(d)h
3.1416(8)(30)=753.98ft^2 plus the area of the base and top cover of the cylinder which is the circle as pi(d^2):
pi(8^2) = 201.06 then summing up to get the total area for the sheet of metal to be used as:
201.06 + 753.98 = 955.04 ft^2 ,
the standard size of metal sheet is 4' x 8' = to the area of 32 ft^2.
dividing the total area to the area of sheet metal would be;
955.04 / 32 = 29.84 sheets, most likely to consume as 30 sheets. hope to give u the right answer!
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